u/According-King3523

Is this textbook step wrong?

The book’s steps are:

  1. Horizontally compress (y=f(x)) by a factor of (1/2) to graph (y=f(2x)).

  2. Shift (y=f(2x)) 1 unit to the right to graph (y=f(2x-1)).

  3. Shift (y=f(2x-1)) 3 units up to graph (y=f(2x-1)+3).

Isnt step 2 wrong? Because the book graphed one point of f(2x-1) = (-1, -1). If we plugged -1 into f(2(-1) - 1) = -3, but the original function is at (-4,-1). Am i missing something?

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u/According-King3523 — 17 days ago