u/Alternative_Cook_102

Today, I will attempt to calc the many piercing blood feats performed by Kenjaku.

Feat 1:- Kenjaku flexes while dodging PB. (ch 203)

Average human eye width:- 25 cm or 0.025 m

Distance between Kenjaku and PB:- 0.04 cm

I will assume, Kenjaku just moved downwards to avoid the attack and did the zesty pose later. Which will be the bare minimum to dodge ts

Kenjaku Height:- 188 cm or 1.88 m

Forehead length or distance travelled:- 0.136 m

#Low-end (mach 1.1)

Timeframe:- (0.04/377.3) = 0.00010601643254 s

Therefore, speed:- (0.136/0.00010601643254) = 1282.9 m/s or mach 3.7

Supersonic+

#High-end (mach 2)

Timeframe:- (0.04/686) = 0.00005830903790087 s

Therefore, speed:- (0.136/0.00005830903790087):- 2332.4 m/s or mach 6.8

Hypersonic

You can also assume that Geto moved his whole body as well, but i don't personally consider it valid.

Assuming Kenjaku simply moved backwards with an angle of around 30° using his torso as the radius. And I will ignore his other movements cause it's easier.

Kenjaku Torso height:- 0.956 m

Then, distance travelled (arc length):- 0.50056 m

I will only use mach 1.1 for this end,

Timeframe:- (0.04/377.3) = 0.00010601643254 s

Therefore, speed:- (0.50056/0.00010601643254) = 4721.5 m/s or mach 13.7

Hypersonic+

Feat 2:- Kenjaku side steps PB (ch 203)

Kenjaku lower face (brow line to chin) length:- 0.13 m

Distance between PB and Kenjaku:- 0.05 m

Distance moved by Kenjaku to avoid PB:- 0.326 m

#Low-end (mach 1.1)

Timeframe:- (0.05/377.3) = 0.00013252054068 s

Therefore, speed:- (0.326/0.00013252054068):- 2460 m/s or mach 7.1

Hypersonic

#High-end (mach 2)

Timeframe:- (0.05/686) = 0.00007288629737609 s

Therefore, speed:- (0.326/0.00007288629737609):- 4472.7 m/s or mach 13

Hypersonic+

Feat 3:- Kenjaku Ducks to dodge PB (ch 204)

Kenjaku's forehead:- 0.062 m

Distance moved by Kenjaku:- 0.753 m

(this is a bit off due to perspective but 2 to 5 cm shouldn't matter)

For the distance between Choso and Kenjaku. I will have to use angsizing by using cm as the pixels in the app.

Distance between Kenjaku and Observer:- 1.2734 m

(since choso is crouched, I will only use half his height. He is about 185 cm tall, being nearly as tall as Geto)

Distance between Choso and Observer:- 6.5603 m

Therefore, distance between Geto and choso:- 5.2869 m

Timeframe:- (5.2869/377.3):- 0.01401245693082 s

Therefore, speed:- (0.753/0.01401245693082) = 53.8 m/s or mach 0.15

Subsonic

(Low tier feat, no point in doing a high end)

Feat 4:- Kenjaku spins his head a little to not die to a point blank PB

Average human finger tip width:- 1.5 cm to 2 cm, I will 1.5 cm or 0.015 m

Distance between Kenjaku and Finger:- 0.03 m

Kenjaku just spins his head to mitigate the attack instead of directly Dodging. So, I will find that.

Kenjaku head width (nose to ear):- 0.14 m

Assuming, he did about a 45° spin. So, Distance travelled (arc length):- 0.1099557 m

#Low-end (mach 1.1)

Timeframe:- (0.03/377.3) = 0.00007951232441028 s

Therefore, speed:- (0.1099557/0.00007951232441028) = 1382.9 m/s or mach 4.03

Supersonic+

#High-end (mach 2)

Timeframe:- (0.03/686) = 0.00004373177842565

Therefore, speed:- (0.1099557/0.00004373177842565) = 2514.3 m/s or mach 7.3

Hypersonic

Conclusion,

>Feat 1

Low-end:- Mach 3.7 (Supersonic+)

High-end:- Mach 6.8 (Hypersonic)

Alternative method:- mach 13. 7 (Hypersonic+)

>Feat 2

Low-end:- Mach 7.1 (Hypersonic)

High-end:- Mach 13 (Hypersonic+)

>Feat 3

Mach 0.15 (Subsonic)

>Feat 4

Low-end:- Mach 4.03 (Supersonic+)

High-end:- 7.3 (Hypersonic)

Today, I will attempt to calc the many piercing blood feats performed by Kenjaku.

Feat 1:- Kenjaku flexes while dodging PB. (ch 203)

Average human eye width:- 25 cm or 0.025 m

Distance between Kenjaku and PB:- 0.04 cm

I will assume, Kenjaku just moved downwards to avoid the attack and did the zesty pose later. Which will be the bare minimum to dodge ts

Kenjaku Height:- 188 cm or 1.88 m

Forehead length or distance travelled:- 0.136 m

#Low-end (mach 1.1)

Timeframe:- (0.04/377.3) = 0.00010601643254 s

Therefore, speed:- (0.136/0.00010601643254) = 1282.9 m/s or mach 3.7

Supersonic+

#High-end (mach 2)

Timeframe:- (0.04/686) = 0.00005830903790087 s

Therefore, speed:- (0.136/0.00005830903790087):- 2332.4 m/s or mach 6.8

Hypersonic

You can also assume that Geto moved his whole body as well, but i don't personally consider it valid.

Assuming Kenjaku simply moved backwards with an angle of around 30° using his torso as the radius. And I will ignore his other movements cause it's easier.

Kenjaku Torso height:- 0.956 m

Then, distance travelled (arc length):- 0.50056 m

I will only use mach 1.1 for this end,

Timeframe:- (0.04/377.3) = 0.00010601643254 s

Therefore, speed:- (0.50056/0.00010601643254) = 4721.5 m/s or mach 13.7

Hypersonic+

Feat 2:- Kenjaku side steps PB (ch 203)

Kenjaku lower face (brow line to chin) length:- 0.13 m

Distance between PB and Kenjaku:- 0.05 m

Distance moved by Kenjaku to avoid PB:- 0.326 m

#Low-end (mach 1.1)

Timeframe:- (0.05/377.3) = 0.00013252054068 s

Therefore, speed:- (0.326/0.00013252054068):- 2460 m/s or mach 7.1

Hypersonic

#High-end (mach 2)

Timeframe:- (0.05/686) = 0.00007288629737609 s

Therefore, speed:- (0.326/0.00007288629737609):- 4472.7 m/s or mach 13

Hypersonic+

Feat 3:- Kenjaku Ducks to dodge PB (ch 204)

Kenjaku's forehead:- 0.062 m

Distance moved by Kenjaku:- 0.753 m

(this is a bit off due to perspective but 2 to 5 cm shouldn't matter)

For the distance between Choso and Kenjaku. I will have to use angsizing by using cm as the pixels in the app.

Distance between Kenjaku and Observer:- 1.2734 m

(since choso is crouched, I will only use half his height. He is about 185 cm tall, being nearly as tall as Geto)

Distance between Choso and Observer:- 6.5603 m

Therefore, distance between Geto and choso:- 5.2869 m

Timeframe:- (5.2869/377.3):- 0.01401245693082 s

Therefore, speed:- (0.753/0.01401245693082) = 53.8 m/s or mach 0.15

Subsonic

(Low tier feat, no point in doing a high end)

Feat 4:- Kenjaku spins his head a little to not die to a point blank PB

Average human finger tip width:- 1.5 cm to 2 cm, I will 1.5 cm or 0.015 m

Distance between Kenjaku and Finger:- 0.03 m

Kenjaku just spins his head to mitigate the attack instead of directly Dodging. So, I will find that.

Kenjaku head width (nose to ear):- 0.14 m

Assuming, he did about a 45° spin. So, Distance travelled (arc length):- 0.1099557 m

#Low-end (mach 1.1)

Timeframe:- (0.03/377.3) = 0.00007951232441028 s

Therefore, speed:- (0.1099557/0.00007951232441028) = 1382.9 m/s or mach 4.03

Supersonic+

#High-end (mach 2)

Timeframe:- (0.03/686) = 0.00004373177842565

Therefore, speed:- (0.1099557/0.00004373177842565) = 2514.3 m/s or mach 7.3

Hypersonic

Conclusion,

>Feat 1

Low-end:- Mach 3.7 (Supersonic+)

High-end:- Mach 6.8 (Hypersonic)

Alternative method:- mach 13. 7 (Hypersonic+)

>Feat 2

Low-end:- Mach 7.1 (Hypersonic)

High-end:- Mach 13 (Hypersonic+)

>Feat 3

Mach 0.15 (Subsonic)

>Feat 4

Low-end:- Mach 4.03 (Supersonic+)

High-end:- 7.3 (Hypersonic)